How to define a string literal bounded by double quotes as a raw string?

val str = """"abc""""

On Sun, Mar 7, 2010 at 6:02 PM, ZhangQidi wrote:
> For example, the string is "abc"(including two double quotes)
>
> val str = """\"abc\""""
>
> The above expression cannot work at all.
>
>
>
>

With raw strings, everything between triple-quotes is part of the string, _including_ quotes.  The only problem is if you have 6 or more quotes in a row (6 quotes in a row = the empty string).

Thus:

scala> "\"\"not raw\"\""
res0: java.lang.String = ""not raw""

scala> """""raw"""""
res1: java.lang.String = ""raw""

scala> "\"not raw\""
res2: java.lang.String = "not raw"

scala> """"raw""""
res3: java.lang.String = "raw"

  --Rex

On Sun, Mar 7, 2010 at 5:02 AM, ZhangQidi <zhangqidicn@yahoo.com.cn> wrote:

For example, the string is "abc"(including two double quotes)

val str = """\"abc\""""

The above expression cannot work at all.

Well... my scala version is 2.7.7, jvm1.6, the compiler doesn't allow the following:

val str = """"abc""""

error: unterminated string

is it a bug or something?

Ah, sorry, this was changed in 2.8; there it works the more useful way.

In 2.7.7, you are out of luck--if you want to add quotes to your string you'll need to use some other method:

scala> "\"" + """raw""" + "\""
res0: java.lang.String = "raw"

scala> def quote(s: String) = "\"" + s + "\""
quote: (String)java.lang.String

scala> quote("""raw""")
res1: java.lang.String = "raw"

scala> def quotes(s: String, n: Int) = ("\""*n) + s + ("\""*n)
quotes: (String,Int)java.lang.String

scala> quotes("""raw""",5)
res2: java.lang.String = """""raw"""""

  --Rex

On Sun, Mar 7, 2010 at 5:43 AM, ZhangQidi <zhangqidicn@yahoo.com.cn> wrote:

Well... my scala version is 2.7.7, jvm1.6, the compiler doesn't allow the following:

val str = """"abc""""

error: unterminated string

is it a bug or something?

I see. It's not something serious, and there's many walk arounds. I just feel it odd.