Tuple15FromExpr
given Tuple15FromExpr[T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15](using val x$1: Type[T1], val x$2: Type[T2], val x$3: Type[T3], val x$4: Type[T4], val x$5: Type[T5], val x$6: Type[T6], val x$7: Type[T7], val x$8: Type[T8], val x$9: Type[T9], val x$10: Type[T10], val x$11: Type[T11], val x$12: Type[T12], val x$13: Type[T13], val x$14: Type[T14], val x$15: Type[T15], val x$16: FromExpr[T1], val x$17: FromExpr[T2], val x$18: FromExpr[T3], val x$19: FromExpr[T4], val x$20: FromExpr[T5], val x$21: FromExpr[T6], val x$22: FromExpr[T7], val x$23: FromExpr[T8], val x$24: FromExpr[T9], val x$25: FromExpr[T10], val x$26: FromExpr[T11], val x$27: FromExpr[T12], val x$28: FromExpr[T13], val x$29: FromExpr[T14], val x$30: FromExpr[T15]): FromExpr[(T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15)]
Default implementation of FromExpr[Tuple15[...]]
- Transform '{Tuple5(x1, ..., x15)} into Some(Tuple5(x1, ..., x15)) if all xi can be transformed using FromExpr[Ti]
- Otherwise returns None
- Source
- FromExpr.scala