Tuple5FromExpr
Default implementation of FromExpr[Tuple5[...]]
- Transform '{Tuple5(x1, ..., x5)}
into Some(Tuple5(x1, ..., x5))
if all xi
can be transformed using FromExpr[Ti]
- Otherwise returns None
- Source:
- FromExpr.scala
Default implementation of FromExpr[Tuple5[...]]
- Transform '{Tuple5(x1, ..., x5)}
into Some(Tuple5(x1, ..., x5))
if all xi
can be transformed using FromExpr[Ti]
- Otherwise returns None