Tuple6ToExpr

given Tuple6ToExpr[T1, T2, T3, T4, T5, T6]: ToExpr[(T1, T2, T3, T4, T5, T6)]

Default implementation of ToExpr[Tuple6[T1, T2, T3, T4, T5, T6]]

Source:
ToExpr.scala

Value members

Concrete methods

def apply(tup: (T1, T2, T3, T4, T5, T6))(using Quotes): Expr[(T1, T2, T3, T4, T5, T6)]