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Scala 3/scala/Function16

Function16

scala.Function16
trait Function16[-T1, -T2, -T3, -T4, -T5, -T6, -T7, -T8, -T9, -T10, -T11, -T12, -T13, -T14, -T15, -T16, +R] extends AnyRef

A function of 16 parameters.

Attributes

Source
Function16.scala
Graph
Supertypes
class Object
trait Matchable
class Any
Known subtypes
class AbstractFunction16[T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15, T16, R]
Self type
(T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15, T16) => R

Members list

Value members

Abstract methods

def apply(v1: T1, v2: T2, v3: T3, v4: T4, v5: T5, v6: T6, v7: T7, v8: T8, v9: T9, v10: T10, v11: T11, v12: T12, v13: T13, v14: T14, v15: T15, v16: T16): R

Apply the body of this function to the arguments.

Apply the body of this function to the arguments.

Attributes

Returns

the result of function application.

Source
Function16.scala

Concrete methods

def curried: T1 => T2 => T3 => T4 => T5 => T6 => T7 => T8 => T9 => T10 => T11 => T12 => T13 => T14 => T15 => T16 => R

Creates a curried version of this function.

Creates a curried version of this function.

Attributes

Returns

a function f such that f(x1)(x2)(x3)(x4)(x5)(x6)(x7)(x8)(x9)(x10)(x11)(x12)(x13)(x14)(x15)(x16) == apply(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16)

Source
Function16.scala
override def toString(): String

Returns a string representation of the object.

Returns a string representation of the object.

The default representation is platform dependent.

Attributes

Returns

a string representation of the object.

Definition Classes
Any
Source
Function16.scala
def tupled: ((T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, T14, T15, T16)) => R

Creates a tupled version of this function: instead of 16 arguments, it accepts a single scala.Tuple16 argument.

Creates a tupled version of this function: instead of 16 arguments, it accepts a single scala.Tuple16 argument.

Attributes

Returns

a function f such that f((x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16)) == f(Tuple16(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16)) == apply(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16)

Source
Function16.scala
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Copyright (c) 2002-2024, LAMP/EPFL
Copyright (c) 2002-2024, LAMP/EPFL