Scala 3
3.5.2
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Scala 3/scala/Function6

Function6

scala.Function6
trait Function6[-T1, -T2, -T3, -T4, -T5, -T6, +R] extends AnyRef

A function of 6 parameters.

Attributes

Source
Function6.scala
Graph
Supertypes
class Object
trait Matchable
class Any
Known subtypes
class AbstractFunction6[T1, T2, T3, T4, T5, T6, R]
Self type
(T1, T2, T3, T4, T5, T6) => R

Members list

Value members

Abstract methods

def apply(v1: T1, v2: T2, v3: T3, v4: T4, v5: T5, v6: T6): R

Apply the body of this function to the arguments.

Apply the body of this function to the arguments.

Attributes

Returns

the result of function application.

Source
Function6.scala

Concrete methods

def curried: T1 => T2 => T3 => T4 => T5 => T6 => R

Creates a curried version of this function.

Creates a curried version of this function.

Attributes

Returns

a function f such that f(x1)(x2)(x3)(x4)(x5)(x6) == apply(x1, x2, x3, x4, x5, x6)

Source
Function6.scala
override def toString(): String

Returns a string representation of the object.

Returns a string representation of the object.

The default representation is platform dependent.

Attributes

Returns

a string representation of the object.

Definition Classes
Any
Source
Function6.scala
def tupled: ((T1, T2, T3, T4, T5, T6)) => R

Creates a tupled version of this function: instead of 6 arguments, it accepts a single scala.Tuple6 argument.

Creates a tupled version of this function: instead of 6 arguments, it accepts a single scala.Tuple6 argument.

Attributes

Returns

a function f such that f((x1, x2, x3, x4, x5, x6)) == f(Tuple6(x1, x2, x3, x4, x5, x6)) == apply(x1, x2, x3, x4, x5, x6)

Source
Function6.scala
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Copyright (c) 2002-2024, LAMP/EPFL
Copyright (c) 2002-2024, LAMP/EPFL