Overriding a method that returns a repeated parameter

Given a method that returns a repeated parameter (getXs below):

> scala> class A(xs: Int*) { def getXs = xs }
> defined class A

Is there any way to override that method? I've tried a whole pile of different constructs, none of which work:

> scala> class B extends A { override def getXs: Seq[Int] = Seq() }
> :8: error: overriding method getXs in class A of type => Int*;
> method getXs has incompatible type
> class B extends A { override def getXs: Seq[Int] = Seq() }
> ^
>
> scala> class B extends A { override def getXs: collection.mutable.WrappedArray[Int] = Array[Int]() }
> :8: error: overriding method getXs in class A of type => Int*;
> method getXs has incompatible type
> class B extends A { override def getXs: collection.mutable.WrappedArray[Int] = Array[Int]() }
> ^
>
> scala> class B extends A { override def getXs: Int* = Array[Int]() }
> :1: error: '=' expected but identifier found.
> class B extends A { override def getXs: Int* = Array[Int]() }
> ^
> :1: error: illegal start of simple expression
> class B extends A { override def getXs: Int* = Array[Int]() }
> ^

Is there any way to do this? I did find this related question on SO, but the answer was (to me, at least) unedifying:

http://stackoverflow.com/questions/5512402/overriding-a-repeated-class-p...

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