Getting a full XPath from an XML Node

Hello,
I am trying to replicate some java functionality which converts XML
elements into Java style properties (e.g. "foo.bar.length"). the following
Java snippet:

XPath all = dom.getRootElement().createXPath("//*");
List< ? > results = all.selectNodes(dom.getRootElement());

using this XML:

hello
red

gives (with some more code not pasted here..) these 2 properties:

goal.name=hello
goal.color=red

I have tried to do this with Scala Xpath's like queries but am having issues
with getting a full XPath from each Node object in "kids" NodeSeq . Here is
my code and am happy for alternative approaches on this.

val xmldoc = XML.loadFile(configFile)
val kids = xmldoc \\ "_"
kids.foreach(child => printXPath(child)) // calls my function

The printXPath function uses Node method descendant_or_self to manually
build XPath

So my question is - How can I get full XPath from an XML Node using Scala.
The only option I can think of is to use the Java XPath libraries (commonly
using Java 6 SDK or Jaxen) in Scala - but I am hoping to find a
Scala-centric solution.

Regards,
Serge