a xml elem problem

That would require full recursion on every child Node, which would be rather expensive. Just don't do it.

2009/12/15 Caesar You <Caesar.Jr@hotmail.com>

is scala.xml.Elem lack of a way to detect a "ring" in the tree? that is, if Elem's last parameter(Node*) includes itself, that will causes a infinited recursive.

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Daniel C. Sobral

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2009/12/15 Caesar You <Caesar.Jr@hotmail.com>

is scala.xml.Elem lack of a way to detect a "ring" in the tree? that is, if Elem's last parameter(Node*) includes itself, that will causes a infinited recursive.

You need to supply the Node * parameters during the construction of the Elem.  But you won't have the instance of the Elem to put in the Node* list during construction, so I don't see how such a case could ever exist.



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On Tue, Dec 15, 2009 at 07:59:16AM -0800, David Pollak wrote:
> You need to supply the Node * parameters during the construction of
> the Elem. But you won't have the instance of the Elem to put in the
> Node* list during construction, so I don't see how such a case could
> ever exist.

scala> object o {
lazy val e1: xml.Elem = xml.Elem(null, "a", null, null, e2)
lazy val e2: xml.Elem = xml.Elem(null, "b", null, null, e1)
}
defined module o

scala> o.e1
java.lang.StackOverflowError
at o$.e1(:4)