Hello Scala Users,

This is a newbie question:
I am trying to build a simple scala web server using jetty embedded. My
scala code is:

--------------------- file jetty_handler.scala
----------------------------------
import org.mortbay.jetty.Server
import org.mortbay.jetty.Request
import org.mortbay.jetty.handler.DefaultHandler
import org.mortbay.jetty.handler.ResourceHandler
import org.mortbay.jetty.handler.ContextHandler
import org.mortbay.jetty.handler.AbstractHandler
import javax.servlet.http.HttpServletRequest
import javax.servlet.http.HttpServletResponse

class MutableHandler extends AbstractHandler {
var html = "

Hello

"

override def handle(target: String, request: HttpServletRequest,
response: HttpServletResponse, dispatch:Int ) = {
response.setContentType("text/html");
response.setStatus(HttpServletResponse.SC_OK);
response.getWriter().println(html.toString());
(request.asInstanceOf[Request]).setHandled(true);
}
}

var server = new Server(8080)
var handler= new MutableHandler()
server.setHandler(handler)
server.start()

--------------------------------------------------

when I run the program using:

scala jetty_handler.scala

the socket does not listen on port 8080, however, when I start the
interactive mode using 'scala' and then cut and paste the above code,
the server does listen on the port 8080.
Do we have an explanation to that phenomenon?
What should I do to start a program that listen on a socket? Create a
'package' and have it run using java?

Thanks in advance
Tux