Re: More elegant way of reading HTML from a URL than this?

Even better:

def read(url:String):String = io.Source.fromURL(url).mkString

Ken
On Jan 21, 2009, at 10:42 AM, Seth Tisue wrote:

>>>>>> "Kenneth" == Kenneth McDonald
>>>>>> writes:
>
> Kenneth> Here's a bit of code I wrote to read the HTML from a URL, and
> Kenneth> return it as a string. I was wondering if a Scala guru could
> Kenneth> show me the "right" way to do this. I'm sure there's a more
> Kenneth> elegant solution.
>
> def read(url:String):String =
> io.Source.fromInputStream(new
> java.net.URL(url).openStream()).mkString
> println(read("http://www.yahoo.com/"))
>